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Explain solution RD Sharma class 12 chapter Probability exercise 30.6 question 12 maths

Answers (1)

Answer:

 \frac{59}{105}

Hint:

 To solve this we make two case and then use total probability formula

Given:

Bag 1 – 6R + 8B

Bag 2 – 8R + 6B

Solution:

\begin{aligned} &\text { Case 1: Red ball is transferred }=\frac{6}{14}\times \frac{9}{15}\\ &\text { Case 2: Black ball is transferred }=\frac{8}{14}\times \frac{8}{15}\\ &P=\text { Case 1 + Case 2 }\\ &P=\frac{6}{14}\times \frac{9}{15}+\frac{8}{14}\times \frac{8}{15}\\ &=\frac{54+64}{14\times 15}=\frac{118}{14\times 15}=\frac{118}{210}\\ &=\frac{59}{105} \end{aligned}

Posted by

Gurleen Kaur

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