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  • Need solution for RD Sharma maths class 12 chapter Probability exercise 30.2 question 6 subquestion (ii)

Need solution for RD Sharma maths class 12 chapter Probability exercise 30.2 question 6 subquestion (ii)

Answers (1)

Answer:

 \frac{4}{663}

Hint:

 \begin{aligned} &\text { Probability }=\frac{\text { No. of event favourable outcomes }}{ \text { Total no. of outcomes }} \end{aligned}

Given Events

Let A= A king in 1st draw

B= An ace in the 2nd draw

Solution:

\begin{aligned} &P(A)=\frac{4}{52}=\frac{1}{13}\\ &P\left ( \frac{B}{A} \right )=\frac{4}{51}\\ &\text { Required Probability }=P(A\cap B)\\ &=P(A)\times P\left ( \frac{B}{A} \right )\\ &=\frac{1}{13}\times \frac{4}{51}\\ &=\frac{4}{663} \end{aligned}

Posted by

Gurleen Kaur

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