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  • Need Solution for R.D.Sharma Maths Class 12 Chapter 30 Probability Exercise 30.5 Question 24 Sub Question 2 Maths Textbook Solution.

Need Solution for R.D.Sharma Maths Class 12 Chapter 30 Probability  Exercise 30.5 Question 24 Sub Question 2 Maths Textbook Solution.

Answers (1)

Answer:0.28

Hint: P\left ( \bar{A} \right )=1-P\left ( A \right )

Given:

P\left ( {A} \: grade\: in\: maths\right )=0.2=P\left ( A \right )

P\left ( {A} \: grade\: in\: Physics\right )=0.3=P\left ( B \right )

P\left ( {A} \: grade\: in\: Chemistry\right )=0.5=P\left ( C \right )

Solution: P(grade A in no subject)

\begin{aligned} &=P(\bar{A}) \times P(\bar{B}) \times P(\bar{C}) \\ &=(1-0.2) \times(1-0.3) \times(1-0.5) \\ &=0.8 \times 0.7 \times 0.5 \\ &=0.28 \end{aligned}

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