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Provide Solution For  R.D. Sharma Maths Class 12 Chapter 30 Probaility  Exercise 30.5 Question 14 Sub Question 2 Maths Textbook Solution.

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Answer:\frac{2}{7}

Hint: You must know the rules of finding probability.

Given:

Probability of husband's will selected =\frac{1}{7}=P(A)

Probability of wife will selected =\frac{1}{5}=P(B)

Solution:

\begin{aligned} &P(\text { husband selected })=\frac{1}{7} \\ &P(\text { wife selected })=\frac{1}{5} \end{aligned}

\begin{aligned} &P(\text { one of them will be selected })=P(A) P(\bar{B})+P(\bar{A}) P(B) \\ \end{aligned}

\begin{aligned} &=\frac{1}{7}\left(1-\frac{1}{5}\right)+\frac{1}{5}\left(1-\frac{1}{7}\right) \\ &=\frac{1}{7}\left(\frac{4}{5}\right) \times \frac{1}{5}\left(\frac{6}{7}\right) \\ &=\frac{4}{35}+\frac{6}{35} \\ &=\frac{10}{35} \\ &=\frac{2}{7} \end{aligned}

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