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Need Solution for R.D.Sharma Maths Class 12 Chapter 30 Probability  Exercise 30.5 Question 20 Sub Question 2 Maths Textbook Solution.

Answers (1)

Answer: \frac{47}{90}

Hint: You must know the rules of finding probability.

Given:

Bag\left ( A \right )\rightarrow \left ( 4R+5B \right )balls

Bag\left ( B \right )\rightarrow \left ( 3R+7B \right )balls

Solution:

Total no. of balls = 9 balls in bag A

Total no. of balls =10 balls in bag B

 P (balls of same colors) = P (both red) + P (both black )

=\left ( \frac{4}{9}\times \frac{3}{10} \right )+\left ( \frac{7}{10}\times \frac{5}{9} \right )

=\frac{12}{90}+\frac{35}{90}

=\frac{47}{90}

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