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Provide Solution For  R.D. Sharma Maths Class 12 Chapter 30 Probaility  Exercise 30.4 Question 6 Sub Question 6 Maths Textbook Solution.

Answers (1)

Answer: 0.3

Hint: Using P\left ( \frac{A}{B} \right )=\frac{P\left ( A\cap B \right )}{P\left ( B \right )}

Given,

            P\left ( A \right )=0.3

            P\left ( B \right )=0.6

Solution:

 As we know, Two events are said to be independent if the product of the events are equal to their intersection. i.e. P\left ( A\cap B \right )=P\left ( A \right )P\left ( B \right )

                        \begin{aligned} P\left(\frac{A}{B}\right) &=\frac{P(A \cap B)}{P(B)} \\ &=\frac{P(A) P(B)}{P(B)} \\ &=0.3 \end{aligned}

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