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Explain solution RD Sharma class 12 chapter Probability exercise 30.2 question 4 maths

Answers (1)

Answer:

 \frac{11}{50}

Hint:

Consider events for tickets and use probability formula

Given, 12 even number between 1 to 25

Solution:

Let,

A = An even number ticket in the first draw

B = An even number ticket in the second draw

Now,

\begin{aligned} &P(A)=\frac{12}{25}\\ &P\left (\frac{B}{A} \right )=\frac{11}{25}\\ &\text { Required Probability }=P(A\cap B)\\ &=P(A)\times P\left ( \frac{B}{A} \right )\\ &=\frac{15}{25}\times \frac{11}{24}\\ &=\frac{11}{50} \end{aligned}

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Gurleen Kaur

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