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  • Need Solution for R.D. Sharma Maths Class 12 Chapter 30 Probability Exercise 30.4 Question 14 Maths Textbook Solution.

Need Solution for R.D.  Sharma Maths Class 12 Chapter 30 Probability  Exercise 30.4 Question 14 Maths Textbook Solution.

Answers (1)

Answer:\frac{9}{25},\frac{4}{25},\frac{6}{25}

 Hint: Probability=\frac{No\: of\: outcomes}{Total\: outcomes}

Given, A Bag contains 3 red & 2 black balls. One ball is drawn at random. Its color is noted and then it is put back in the bag. A second drawn is made and the same procedure is repeated.

Solution:

Let 3 red balls be R_{1},R_{2}, & R_{3} and 2 black balls be B_{1} & B_{2}.

                      Total Possibilities = \begin{gathered} \left\{\left(R_{1}, R_{2}\right),\left(R_{1}, R_{3}\right),\left(R_{1}, B_{1}\right),\left(R_{1}, B_{2}\right),\left(B_{1}, B_{2}\right),\left(R_{2}, R_{1}\right) \right. \\ \end{gathered}

        \begin{gathered} \left(R_{2}, R_{3}\right),\left(R_{2}, B_{1}\right),\left(R_{2}, B_{2}\right),\left(R_{3}, R_{1}\right),\left(R_{3}, R_{2}\right),\left(R_{3}, B_{1}\right),\left(R_{3}, B_{2}\right),\left(R_{1}, R_{1}\right),\left(R_{2}, R_{2}\right),\left(R_{3}, R_{3}\right) \\ \left.\left(B_{1}, B_{1}\right),\left(B_{2}, B_{2}\right),\left(B_{1}, R_{1}\right),\left(B_{1}, R_{2}\right),\left(B_{1}, R_{3}\right),\left(B_{2}, R_{1}\right),\left(B_{2}, R_{2}\right),\left(B_{2}, R_{3}\right),\left(B_{2}, B_{1}\right)\right\} \end{gathered}

                   i.               Probability of drawing two red balls=\frac{9}{25}

                     ii.                Probability of drawing two black balls =\frac{4}{25}

                    iii.                Probability of first red and second black =\frac{6}{25}

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