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Please Solve R.D. Sharma class 12 Chapter 30 Probaility  Exercise 30.5 Question 4 Maths Textbook Solution.

Answers (1)

Answer:\frac{32}{221}

Hint: You must know the rules of finding probability .

Given: Two cards are drawn from 52 cards without replacement

Solution: P(exactly one ace)=P(first card ace)+P(second not ace)

\begin{aligned} =&\left(\frac{4}{52} \times \frac{48}{51}\right)+\left(\frac{48}{52} \times \frac{4}{51}\right) \\ =& \frac{192+192}{52 \times 51} \\ =& \frac{384}{52 \times 51} \\ =& \frac{32}{221} \end{aligned}

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