Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain Solution R.D. Sharma Class 12 Chapter 30 Probability Exercise Multiple Choice Questions Question 57 Maths Textbook Solution.

Explain Solution R.D. Sharma Class 12 Chapter 30 Probability  Exercise Multiple Choice Questions  Question 57 Maths Textbook Solution.

Answers (1)

Answer:(d)

Hint: You must know the rules of finding probability.

Given: in the family each child is equally likely to be boy or a girl.

A family with three children chosen at random.

Solution: we have, B – Boy    ,    G – girl

S = {BBB ,BBG , BGB , BGG , GGG , GBG , GGB , GBB}

Let

 A be the event of selected family with girl and

B be the event of selecting family with least one girls

So,

\begin{aligned} &A=\{G G G, G B G, G G B, G B B\} \text { and } \\\\ &B=\{B B B, B B G, B G B, B G G, G G G, G B G, G G B, G B B\} \\\\ &\therefore n(A)=4, n(B)=7, n(A \cap B)=n(A)=4 \end{aligned}

Now,

P\left(\frac{A}{B}\right)=\frac{n(A \cap B)}{n(B)}=\frac{4}{7}

Posted by

infoexpert21

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Board exams twice a year from 2025, no plan for semesters: MoE
anam-khan

CBSE Class 12 board exams 2025 to have 50% competency-based questions; no change in 10th
anam-khan

CBSE Class 12 board exams 2024 over; expected result date, trends of last 10 years

Latest Question