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Need Solution for R.D.Sharma Maths Class 12 Chapter 30 Probability  Exercise 30.5 Question 29 Maths Textbook Solution.

Answers (1)

Answer:\frac{39}{80}

Hint: You must know the rules of finding probability functions.

Given:

Bag-A\rightarrow \left ( 3R+5B \right )

Bag-B\rightarrow \left ( 2R+3B \right )

Solution:

It is given that bag A contains 3 red and 5 black balls and bag B contains (2R,3B)

Total no. of balls in bag A = 8 balls

Total no. of balls in bag B =5 balls

P\left ( one\: red\: and\: 2\: black \right )=

P\left ( 1\: red\: from\: bag\: A\: and\:2\: black\: from\: bagB \right )+P\left ( black\: ball\: from\: bag\: A\: and\: remaining\: from\: B \right )

\begin{aligned} &=\left(\frac{3}{8} \times \frac{3}{5} \times \frac{2}{4}\right)+\frac{5}{8} \times \frac{2}{5} \times \frac{3}{4} \times 2 \\ \end{aligned}

\begin{aligned} &=\frac{9}{80}+\frac{30}{80}=\frac{39}{80} \end{aligned}

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