Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Provide solution for RD Sharma maths class 12 chapter Probability exercise 30.2 question 2

Provide solution for RD Sharma maths class 12 chapter Probability exercise 30.2 question 2

Answers (1)

Answer:

 \frac{1}{270725}

Hint:

\text { Probability }=\frac{\text { No. of favourable outcomes }}{ \text { Total no. of outcomes }}

Solution:

Let, A = An ace in the first draw.

        B = An ace in the 2nd draw.

        C = An ace in the 3rd draw.

        D =  An ace in the 4th draw.

\begin{aligned} &\text { Probability of A }=\frac{4}{25}\\ &=\frac{1}{13}\\ &P\left ( \frac{B}{A} \right )=\frac{3}{51}=\frac{1}{17}\\ &P\left ( \frac{C}{A\cap B} \right )=\frac{2}{50}=\frac{1}{25}\\ &P\left ( \frac{D}{A\cap B\cap C} \right )=\frac{1}{49} \end{aligned}

\begin{aligned} &\text { Required Probability }=P\left ( A\cap B\cap C\cap D \right )\\ &=P(A)\times P\left ( \frac{B}{A} \right )\times P\left ( \frac{C}{A\cap B} \right )\times P\left ( \frac{D}{A\cap B\cap C} \right )\\ &=\frac{1}{13}\times \frac{1}{17}\times \frac{1}{25}\times \frac{1}{49}\\ &=\frac{1}{270725} \end{aligned}

Posted by

Gurleen Kaur

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Admit Card 2026 (OUT) LIVE: Class 10 and 12 theory exam hall ticket at parikshasangam.cbse.gov.in
anam-khan

CBSE Admit Card 2026 LIVE: How to download CBSE Class 10th, 12th hall ticket when out; exam dates, guidelines
anam-khan

CBSE 2026 Admit Card LIVE: CBSE Class 10, 12 hall ticket soon at cbse.gov.in; direct link, datesheet, updates

Latest Question