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Provide Solution For  R.D. Sharma Maths Class 12 Chapter 30 Probaility  Exercise 30.5 Question 12 Maths Textbook Solution.

Answers (1)

Answer:\frac{4}{45}

Hint: You must know the rules of finding probability functions.

Given: Tickets are number from 1 to 10

Two tickets are drawn one after the other at random.

Solution: We know 5 and 10 are multiples of 5 while 4 and 8 are multiples of 4

\begin{aligned} &P(\text { Multiple of } 5)=\frac{2}{10}=\frac{1}{5} \\ &P(\text { Multiple of } 4)=\frac{2}{10}=\frac{1}{5} \end{aligned}

P(Multiple\: of \: 5\: and \: multiply \: of \: 4)=P( multiple\: of \: 5 \: on \: first and \: multiple \: of \: 4 \: on \: second)+

P(multiple of 4 on first and multiple of 5 on second)

\begin{aligned} &=\left(\frac{2}{10} \times \frac{2}{9}\right)+\left(\frac{2}{10} \times \frac{2}{9}\right) \\ \end{aligned}      \left [ without\: replacement \right ]
 

\begin{aligned} &=\frac{4}{90}+\frac{4}{90} \\ &=\frac{8}{90} \\ &=\frac{4}{45} \end{aligned}

 

 

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