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Explain solution RD Sharma class 12 chapter Probability exercise 30.1 question 4 maths

Answers (1)

Answer:

 \frac{1}{2}

Hint:

\text { Probability }=\frac{\text { No. of elements required }}{ \text { Total no. of elements }}

Given, two events

Let,    B         = Event of getting head on toss third

                       = { HHH, HTH, THH, TTH }

Similarly, A  =  Event of getting head on first two tosses

                     = { HHH, HHT }

Now,

  A∩B       = { HHH }

Therefore,

Required probability

\begin{aligned} &=\frac{n(A\cap B)}{n(A)}\\ &=\frac{1}{2} \end{aligned}

Posted by

Gurleen Kaur

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