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Need Solution for R.D.Sharma Maths Class 12 Chapter 30 Probability  Exercise 30.4 Question 17 Maths Textbook Solution.

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Answer: \frac{3}{5}

Hint: Use, P\left ( A\cup B \right )=P(A)+P\left ( B \right )-P\left ( A\cap B \right )

Given, Possibilities

          P\left ( A \right )=P  (A hits target) =\frac{1}{3}

           P\left ( B \right )=P  (B hits target) =\frac{2}{5}

 

Solution: As we know, Two events are said to be independent if the product of the events are equal to their intersection. i.e. P\left ( A\cap B \right )=P\left ( A \right )P\left ( B \right )

            P\left ( A \cup B \right )=P(target will be hit by either A or B)

            \begin{aligned} P(A \cup B) &=P(A)+P(B)-P(A \cap B) \\ P(A \cup B) &=P(A)+P(B)-P(A) P(B) \\ &=\frac{1}{3}+\frac{2}{5}-\frac{1}{3} \times \frac{2}{5} \\ &=\frac{5+6-2}{15} \\ &=\frac{9}{15} \\ &=\frac{3}{5} \end{aligned}

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