Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain Solution R.D.Sharma Class 12 Chapter 30 Probability Exercise 30.4 Question 26 Maths Textbook Solution.

Explain Solution R.D.Sharma Class 12 Chapter 30 Probability  Exercise 30.4 Question 26 Maths Textbook Solution.

Answers (1)

Answer: \frac{126}{1000}

Given: 

             Probability\: of\: finding\: a\: green\: signal\: on\: X=30%

Hint: Probability=\frac{No\: of\: outcomes}{Total\: outcomes}

Solution:

Given,

           Probability\: of\: finding\: a\: green\: signal\: on\: X=\frac{30}{100}=\frac{3}{10}

Probability\: of\:not\: finding\: a\: green\: signal\: on\: X=1-\frac{30}{100}=\frac{7}{10}

                Now, Let D_{1},D_{2},D_{3} be the three days for which the signal is green and D{}'_{1},D{}'_{2},D{}'_{3}   be the three days for not finding a green signal.

                We have to find probability of finding green signal on consecutive two days out of three

                So the event would be \left ( D_{1},D_{2},D{}'_{3} \right ) or\left ( D{}'_{1},D_{2},D_{3} \right )

So the probability of finding green signal on consecutive two days out of three

\begin{aligned} &=\mathrm{P}\left(D_{1}, D_{2}, D_{3}^{\prime}\right)+P\left(D_{1}^{\prime}, D_{2}, D_{3}\right) \\ &=\frac{3}{10} \times \frac{3}{10} \times \frac{7}{10}+\frac{7}{10} \times \frac{3}{10} \times \frac{3}{10} \\ &=\frac{63}{1000}+\frac{63}{1000} \\ &=\frac{126}{1000} \end{aligned}

Posted by

infoexpert21

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

PM Modi's Pariksha Pe Charcha 2025 to be held next month, registrations open till January 14
anam-khan

CBSE Board Exams 2025: Online portal for availing exemptions by CWSN students opens
anam-khan

Board Exams: States agree to equivalence; no question paper ‘jumbling’ from next year, says PARAKH CEO

Latest Question