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  • Need Solution for R.D.Sharma Maths Class 12 Chapter 30 Probability Exercise 30.5 Question 24 Sub Question 3 Maths Textbook Solution.

Need Solution for R.D.Sharma Maths Class 12 Chapter 30 Probability  Exercise 30.5 Question 24 Sub Question 3 Maths Textbook Solution.

Answers (1)

Answer: 0.22

Hint: You must know the rules of finding probability functions.

Given:

\begin{aligned} &P(\mathrm{~A} \text { grade in Maths })=0.2=P(A) \\ &P(\mathrm{~A} \text { grade in Physics })=0.3=P(B) \\ &P(\mathrm{~A} \text { grade in Chemistry })=0.5=P(C) \end{aligned}

Solution:

P(grade A in two subjects) =

P(not grade A in Math )+P(not grade A in Physics)+P(not grade A in Chemistry)

\begin{aligned} &=P(\bar{A}) P(B) P(C)+P(A) P(\bar{B}) P(C)+P(A) P(B) P(\bar{C}) \\\\ &=[(1-0.2) \times 0.3 \times 0.5] \times[0.2 \times(1-0.3) \times 0.5] \times[0.2 \times 0.3 \times(1-0.5)] \\\\ &=[0.8 \times 0.3 \times 0.5] \times[0.2 \times 0.7 \times 0.5] \times[0.2 \times 0.3 \times 0.5] \\\\ &=0.12 \times 0.07 \times 0.03 \\\\ &=0.22 \end{aligned}

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