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  • Provide Solution For R.D. Sharma Maths Class 12 Chapter 30 Probaility Exercise 30.4 Question 11 Maths Textbook Solution.

Provide Solution For  R.D. Sharma Maths Class 12 Chapter 30 Probaility  Exercise 30.4 Question 11 Maths Textbook Solution.

Answers (1)

Answer: \frac{1}{4}

Given: A die is tossed twice. Find the probability of getting a number greater than 3 on each toss.

Hint: Probability=\frac{No\: of\: outcomes}{Total \: Outcomes}

Solution:

Let, S= Total  no. of dice in two throws

        \mathrm{S}=\left\{\begin{array}{l} (1,1),(1,2),(1,3),(1,4),(1,5),(1,6), \\ (2,1),(2,2),(2,3),(2,4),(2,5),(2,6), \\ (3,1),(3,2),(3,3),(3,4),(3,5),(3,6), \\ (4,1),(4,2),(4,3),(4,4),(4,5),(4,6) \\ (5,1),(5,2),(5,3),(5,4),(5,5),(5,6), \\ (6,1),(6,2),(6,3),(6,4),(6,5),(6,6) \end{array}\right\}

         n\left ( S\right )=36

        E=Getting a number greater than 3 on each toss

         \begin{aligned} &\mathrm{E}=\left\{\begin{array}{l} (4,4),(4,5),(4,6),(5,4),(5,5) \\ ,(5,6),(6,4),(6,5),(6,6) \end{array}\right\} \\ &\mathrm{n}(\mathrm{E})=9 \\ &\begin{aligned} \mathrm{P}(\mathrm{E}) &=\frac{\mathrm{n}(\mathrm{E})}{\mathrm{n}(\mathrm{S})} \\ &=\frac{9}{36}=\frac{1}{4} \end{aligned} \end{aligned}

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