Explain Solution R.D. Sharma Class 12 Chapter 30 Probability  Exercise 30.5 Question 32 Sub Question 3 Maths Textbook Solution.

Answers (1)

Answer: \frac{56}{121}

Hint: You must know the rules of finding probability functions.

Given: Urn contains 7 red and 4 blue balls.

Two balls are drawn with replacement

Solution:

P\left ( 1\: red\: balls \: and\: 1\: blue\: ball\right )=

P\left ( blue\: \: balls \: \: followed\: \: by\: \: red\: \: ball\right )+\left ( red\: \: balls \: \: followed\: \: by\: \: blue\: \: ball\right )

\begin{aligned} &=\left(\frac{4}{11} \times \frac{7}{11}\right)+\left(\frac{7}{11} \times \frac{4}{11}\right) \\ &=\frac{28}{121}+\frac{28}{121} \\ &=\frac{56}{121} \end{aligned}

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