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  • Explain Solution R.D. Sharma Class 12 Chapter 30 Probability Exercise Multiple Choice Questions Question 57 Maths Textbook Solution.

Explain Solution R.D. Sharma Class 12 Chapter 30 Probability  Exercise Multiple Choice Questions  Question 57 Maths Textbook Solution.

Answers (1)

Answer:(d)

Hint: You must know the rules of finding probability.

Given: in the family each child is equally likely to be boy or a girl.

A family with three children chosen at random.

Solution: we have, B – Boy    ,    G – girl

S = {BBB ,BBG , BGB , BGG , GGG , GBG , GGB , GBB}

Let

 A be the event of selected family with girl and

B be the event of selecting family with least one girls

So,

\begin{aligned} &A=\{G G G, G B G, G G B, G B B\} \text { and } \\\\ &B=\{B B B, B B G, B G B, B G G, G G G, G B G, G G B, G B B\} \\\\ &\therefore n(A)=4, n(B)=7, n(A \cap B)=n(A)=4 \end{aligned}

Now,

P\left(\frac{A}{B}\right)=\frac{n(A \cap B)}{n(B)}=\frac{4}{7}

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