Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Need solution for RD Sharma maths class 12 chapter Probability exercise 30.7 question 7

Need solution for RD Sharma maths class 12 chapter Probability exercise 30.7 question 7

Answers (1)

Answer:

 \frac{2}{3}

Hint:

Use Baye’s theorem. 

Given:

 Suppose 5 men out of 100 and 25 women out of 1000 are good orator. An orator chose at random. Find the probability that make person is selected. Assume equal number of men and women.

Solution:

Let A, E1and E2  two events that person is good orator.

Thus

\begin{aligned} &P(E_1)=\frac{1}{2}\\ &P(E_2)=\frac{1}{2}\\ &P\left ( \frac{A}{E_1} \right )=\frac{5}{100}\\ &P\left ( \frac{A}{E_2} \right )=\frac{25}{1000}\\ \end{aligned}

Using Baye’s theorem we get

\begin{aligned} &P\left (\frac{E_1}{A} \right )=\frac{P(E_2).P\left ( \frac{A}{E_1} \right )}{P(E_1)\times P\left ( \frac{A}{E_1} \right )+P(E_2)\times P\left ( \frac{A}{E_2} \right )}\\ &P\left (\frac{E_2}{A} \right )=\frac{\frac{1}{2}\times \frac{5}{100}}{\frac{1}{2}\times \frac{5}{100}+\frac{1}{2}\times \frac{25}{1000}}\\ &=\frac{1}{1+\frac{1}{2}}\\ &=\frac{2}{3} \end{aligned}

Posted by

Gurleen Kaur

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE board exams 2025 from February 15; Class 10, 12 subject-wise marks distribution
anam-khan

CBSE Date Sheet 2025: Class 10, 12 board exam dates soon on cbse.gov.in; previous trends, sample papers
anam-khan

CBSE Board Exams 2025: 75% attendance must for students to be eligible, reiterates board

Latest Question