Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please Solve R.D.Sharma class 12 Chapter 30 Probaility Exercise 30.5 Question 3 Sub Question 3 Maths Textbook Solution.

Please Solve R.D.Sharma class 12 Chapter 30 Probaility  Exercise 30.5 Question 3 Sub Question 3 Maths Textbook Solution.

Answers (1)

Answer:\frac{40}{81}

Hint: You must know the rules of finding probability

Given:Box contains 10 black and 8 red balls

Solution:Box = (10B and 8R) balls

 Total no. of balls =10 + 8 = 18 balls

P (one is black and other is red) = P(first red ball and second black)+P(first black ball and second red )

=\left ( \frac{8}{18}\times \frac{10}{18} \right )+\left ( \frac{10}{18}\times \frac{8}{18} \right )

=\frac{80}{324}+\frac{80}{324}

=\frac{160}{324}

=\frac{40}{81}

Posted by

infoexpert21

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Date Sheet 2025: When to expect Class 10, 12 board exam time table?
anam-khan

CBSE introduces CCTV policy in board exams 2025; schools fixed as centres must have facility
anam-khan

CBSE gives parents, schools till October 16 to register students in Classes 9, 11

Latest Question