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Please Solve R.D.Sharma class 12 Chapter 30 Probaility  Exercise 30.5 Question 3 Sub Question 3 Maths Textbook Solution.

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Answer:\frac{40}{81}

Hint: You must know the rules of finding probability

Given:Box contains 10 black and 8 red balls

Solution:Box = (10B and 8R) balls

 Total no. of balls =10 + 8 = 18 balls

P (one is black and other is red) = P(first red ball and second black)+P(first black ball and second red )

=\left ( \frac{8}{18}\times \frac{10}{18} \right )+\left ( \frac{10}{18}\times \frac{8}{18} \right )

=\frac{80}{324}+\frac{80}{324}

=\frac{160}{324}

=\frac{40}{81}

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