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Provide Solution For R.D. Sharma Maths Class 12 Chapter 30 Probaility Exercise 30.5 Question 17 Sub Question 3 Maths Textbook Solution.

Answers (1)

Answer:\frac{13}{24}

Hint: You must know the rules of finding probability functions.

Given:

Bag\left (1 \right )\rightarrow \left ( 4W+2B \right )balls

Bag\left (2 \right )\rightarrow \left ( 3W+5B \right )balls

Solution:

Total no. of balls = 6 balls in bag (1)

Total no. of balls =8 balls in bag (2)

Bag\left (1 \right )\rightarrow \left ( 4W+2B \right )balls

Bag\left (2 \right )\rightarrow \left ( 3W+5B \right )balls

\mathrm{P}( one\: is \: white \: and \: one \: is \: black) =

\mathrm{P}(white from bag 1 and black from 2 bag) +\mathrm{P} (black from bag 1 and white from 1 bag)

\begin{aligned} &=\left(\frac{4}{6} \times \frac{5}{8}\right)+\left(\frac{2}{8} \times \frac{3}{6}\right) \\ &=\frac{20}{48}+\frac{6}{48} \\ &=\frac{26}{48} \\ &=\frac{13}{24} \end{aligned}

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