Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Need solution for RD Sharma maths class 12 chapter Probability exercise 30.7 question 31

Need solution for RD Sharma maths class 12 chapter Probability exercise 30.7 question 31

Answers (1)

Answer:

 \frac{18}{133}

Hint:

 Use Baye’s theorem.

Given:

 Bag A contain 3 red, 5 black, white bag contain 4 red and 4 black. Two ball are transferred at random from bag A to bag B and then a ball B drawn from bag B at random..

Solution:

2 ball drawn from bag A could be both red probability =

\frac{3C_2}{8C_2}

2 one red and one black probability =

\frac{3\times 5}{8C_2}

3 both black probability =

\frac{8C_2}{5C_2}

The no of ball in bag B in each case would be

1. 6 red 4 black = probability pick red =

 \frac{6}{10}

2. 5 red 5 black = probability pick red =

\frac{5}{10}

3. 4 red 6 black = probability pick red =

\frac{4}{10}

Probability of two red ball transfer under the condition that red ball found

Using Baye’s theorem we get

=\frac{\frac{3C_2}{8C_2}\times \frac{6}{10}}{\frac{3C_2}{8C_2}\times \frac{6}{10}+\frac{3\times 5}{8C_2}\times \frac{5}{10}+\frac{3C_2}{5C_2}\times \frac{4}{10}}\\

=\frac{18}{133}

Posted by

Gurleen Kaur

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 board exams 2025 to have 50% competency-based questions; no change in 10th
anam-khan

CBSE Class 12 board exams 2024 over; expected result date, trends of last 10 years

Latest Question