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Please Solve R.D. Sharma class 12 Chapter 30 Probaility  Exercise 30.5 Question 6 Sub Question 1 Maths Textbook Solution.

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Answer:\frac{1}{15}

Hint: You must know the rules of finding probability

Given: Probability of Kamal’s selection=\frac{1}{3}

Probability of Monika’s selection=\frac{1}{5}

Solution: P( Kamal selected)=\frac{1}{3}=P\left ( A \right )

P( Monika selected)=\frac{1}{5}=P\left ( B \right )

P\left ( both\: get\: selected \right )=P\left ( A \right )\times P\left ( B \right )

=\frac{1}{3}\times \frac{1}{5}

=\frac{1}{15}

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