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  • Please Solve R.D. Sharma class 12 Chapter 30 Probaility Exercise 30.5 Question 6 Sub Question 3 Maths Textbook Solution.

Please Solve R.D. Sharma class 12 Chapter 30 Probaility  Exercise 30.5 Question 6 Sub Question 3 Maths Textbook Solution.

Answers (1)

Answer:\frac{7}{15}

Hint: You must know the rules of finding probability

Given:Probability of Kamal’s selection=\frac{1}{3}

Probability of Monika’s selection=\frac{1}{5}

Solution:P( Kamal selected)=\frac{1}{3}=P\left ( A \right )

P( Monika selected)=\frac{1}{5}=P\left ( B \right )

\begin{aligned} &\mathrm{P}(\text { atleast one get selected })=P(A \cup B) \\\\ &P(A \cup B)=P(A)+P(B)-P(A \cap B) \\\\ &=P(A)+P(B)-P(A) P(B) \\ \end{aligned}

\begin{aligned} &=\frac{1}{3}+\frac{1}{5}-\left(\frac{1}{3} \times \frac{1}{5}\right) \\ &=\frac{1}{3}+\frac{1}{5}-\left(\frac{1}{15}\right) \\ &=\frac{5+3-1}{15} \\ &=\frac{7}{15} \end{aligned}

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