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  • Provide solution for RD Sharma maths class 12 chapter Probability exercise 30.2 question 12

Provide solution for RD Sharma maths class 12 chapter Probability exercise 30.2 question 12

Answers (1)

Answer:

 \begin{aligned} &\frac{2}{5525} \end{aligned}

Hint:

\begin{aligned} &\text { Probability }=P(A\cap B\cap C)=P(A)\times P\left ( \frac{B}{A} \right )\times P\left ( \frac{C}{B\cap A} \right ) \end{aligned}

Given, events

            A=A king in the 1st draw

            B=A king in the 2nd draw

\begin{aligned} &P(A)=\frac{4}{52}=\frac{1}{13}\\ &P\left ( \frac{B}{A} \right )=\frac{3}{51}=\frac{1}{17}\\ &P\left ( \frac{C}{B\cap A} \right )=\frac{4}{50}=\frac{2}{25}\\ &\text { Required Probability }=P(A\cap B\cap C)\\ &=P(A)\times P\left ( \frac{B}{A} \right )\times P\left ( \frac{C}{B\cap A} \right )\\ &=\frac{1}{13}\times \frac{1}{17}\times \frac{2}{25}\\ &=\frac{2}{5525} \end{aligned}

Posted by

Gurleen Kaur

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